根据选择, 登录不同账号, 显示不同页面的Python脚本

Python Liemer_Lius 406℃ 0评论

需求:

  • 根据列表, 选择要登录的页面;
  • 根据不同的页面, 选择不同的登录账号, 账号多个, 可以循环;
  • 登录以后的状态可以保留, 在退出后变为False, 下次再次登录;

我们这里用了jingdong和weixin两批账号, 每批账号可以有多个, 写在文件中; 根据不同的选择, 显示不同的页面: Home, Fiance, Book.

# _Author: lWX548594
# _Date: 2018/7/23 0023
# _ScriptName: login

def read_jingdong():   # 定义读取jingdong账号的函数
    global line
    line = {}
    f = open("jingdong", 'r+')
    for lines in f:
        key, value = lines.strip().split()
        line[key] = value

def read_weixin():   # 定义读取微信账号的函数
    global line
    line = {}
    f = open("weixin", 'r+')
    for lines in f:
        key, value = lines.strip().split()
        line[key] = value

def init():         # 初始化函数
    pages = ['Home', 'Fiance', 'Book']
    for i in enumerate(pages, 1):
        print(i)

    choice = input("Please input your choice, q for quit: ")
    while True:
        if choice == 'q':
            print("Exit..........")
            file3 = open('auth_file', 'w')
            file3.write('False')     # q退出, 将auth_file文件写入False, 注意, 这是字符串格式, 不是bool格式.
            exit()
        elif not choice.isdigit():
            print("Please input a number.")
            choice = input("Please input your choice: ")
        elif int(choice) not in range(1, 4):
            print("Out of range...")
            exit()
        else:
            break
    global page_choice      # 函数中的变量, 通常需要声明一下全局, 否则其他函数调用不了, 目前学的少, 以后可能有更好的方法.
    if choice == '1':
        page_choice = "Home"
        read_jingdong()     # 根据不同的页面, 选择读入不同的账号
    elif choice == '2':
        page_choice = "Fiance"
        read_weixin()
    elif choice == '3':
        page_choice = "Book"
        read_jingdong()
    else:
        pass
    auth_file = open('auth_file', 'r')
    global auth_type
    auth_type = auth_file.readline()
    print("auth_type: %s" % auth_type)


def which_flag(flag):     # 装饰器, 传入一个flag, 来确定是否登录
    def login(f):
        def inner(a_choice):
            print("Flag: %s" % flag)
            if flag == 'False':     # 字符串格式, 不是bool...
                print("You have to login first...")
                while True:
                    my_username = input("Please input your username: ")
                    my_pass = input("Please input your password: ")
                    for i in line.keys():     # 循环验证用户
                        break_flag = False
                        if i == my_username:
                            if line[i] == my_pass:
                                print("Login successfully...")
                                file2 = open('auth_file', 'w')
                                file2.write('True')    # 成功后将auth_file写入True
                                break_flag = True
                                break
                    else:
                        print("Wrong username or password. Please try again.")    # 所有账户验证失败, 显示提示信息
                    if break_flag:
                        break
            f(a_choice)
        return inner
    return login

while True:    # 循环开始进行页面显示
    init()
    @which_flag(auth_type)
    def show_page(my_choice):
        print("This is %s page..." % my_choice)
    show_page(page_choice)

其中, weixin和jingdong两个账号密码文件格式如下:

lius 7788
lius1 7788
lius2 7788

auth_file里面事先写入False:

False

脚本运行结果展示:

C:\Users\lwx548594\PycharmProjects\LiusProject\venv\Scripts\python.exe C:/Users/lwx548594/PycharmProjects/LiusProject/Day17/login.py
(1, 'Home')
(2, 'Fiance')
(3, 'Book')
Please input your choice, q for quit: 1
auth_type: False
Flag: False
You have to login first...
Please input your username: lius
Please input your password: 7788
Login successfully...
This is Home page...
(1, 'Home')
(2, 'Fiance')
(3, 'Book')
Please input your choice, q for quit: 3
auth_type: True
Flag: True
This is Book page...
(1, 'Home')
(2, 'Fiance')
(3, 'Book')
Please input your choice, q for quit: 2
auth_type: True
Flag: True
This is Fiance page...
(1, 'Home')
(2, 'Fiance')
(3, 'Book')
Please input your choice, q for quit: q
Exit..........

Process finished with exit code 0

 

以上脚本是自己瞎写的, 有不对的地方, 请大家指正.

 

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